zip:   匹配

>>> k = ['name','year','where']>>> massage = ['tang','18','nc']>>> other = [1,2,3]>>> list(zip(k,massage))[('name', 'tang'), ('year', '18'), ('where', 'nc')]>>> list(zip(k,massage,other))[('name', 'tang', 1), ('year', '18', 2), ('where', 'nc', 3)]

 

lambda:

>>> a =lambda x: x +1>>> a(2)3

filter过滤：

 

>>> li = [1,2,3]>>> a =lambda x: x >2>>> b = filter(a,li)>>> list(b)[3]

 

 

map: 加工

>>> a =lambda x: x +1>>> li = [1,2,3]>>> c=map(a,li)>>> c

 

enumerate枚举：

>>> li=['a','b','c','d']>>> list(enumerate(li))[(0, 'a'), (1, 'b'), (2, 'c'), (3, 'd')]>>> list(enumerate(li,10))[(10, 'a'), (11, 'b'), (12, 'c'), (13, 'd')]for k,v in enumerate(li):print(k,v)>>>0 a1 b2 c3 d

 

进制，ascaii:

bin(3) # '0b11' 二进制前缀 0b

oct(9) # '0o11'

hex(17) # '0x11'

ord('a')

ord('A')

chr(65)

chr(97)

sorted:

sorted(iterable, /, *, key=None, reverse=False)

1)对于一个列表排序

sorted([100, 98, 102, 1, 40])>>>[1, 40, 98, 100, 102]

 

 

2)通过key参数/函数

比如一个长列表里面嵌套了很多字典元素，我们要按照每个元素的长度大小排序

L = [{1:5,3:4},{1:3,6:3},{1:1,2:4,5:6},{1:9}]new_line=sorted(L,key=lambda x:len(x))print(new_line)>>>[{1: 9}, {1: 5, 3: 4}, {1: 3, 6: 3}, {1: 1, 2: 4, 5: 6}]

 

 

3)对由tuple组成的List排序

比如下面是学生里面的年龄的一个list

students = [('wang', 'A', 15), ('li', 'B', 12), ('zhang', 'B', 10)] print(sorted(students, key=lambda x : x[2]))>>>[('zhang', 'B', 10), ('li', 'B', 12), ('wang', 'A', 15)]